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Chemistry - Concentration Terms Question with Solution | TestHub

ChemistryConcentration TermsConcentration termEasy2 minPYQ_2020

ChemistryEasysingle choice

Dissolving 120 g of urea (mol. wt. 60) in 1000 g of water gave a solution of density 1.15 g/ml. The molarity of the solution is

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Answer:

Solution:

Total mass of solution $= 1000 + 120 = 1120 g$
Total volume of solution in $(L) = \frac{1120}{1.15} \times 1 0^{3}$
$M = \frac{W}{M} \times \frac{1}{V (L)} = \frac{120}{60} \times \frac{1.15 \times 1 0^{3}}{1120} = 2.05 M$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Concentration TermsSubtopic:Concentration term

⏱ 2mℹ️ Source: PYQ_2020

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