Chemistry - Concentration Terms Question with Solution | TestHub

ChemistryConcentration TermsConcentration termMedium2 minPYQ_2014

ChemistryMediumassertion reason

The amount of $BaSO_{4}$ formed upon mixing 100 $mL$ of $20.8% BaCl_{2}$ solution with $50 mL$ of $9.8%$ $H_{2} SO_{4}$ solution will be: $(Ba = 137, Cl = 35.5, S = 32, H = 1$ and $O = 16$ )

Options:

Answer:

Solution:

$BaCl_{2} + H_{2} SO_{4} ⟶ BaSO_{4} + 2 HCl$ $208 g 20.8 g 98 g 9.8 g 233 g 23.3 g 73 g 7.3 g$

Stream:JEESubject:ChemistryTopic:Concentration TermsSubtopic:Concentration term

⏱ 2mℹ️ Source: PYQ_2014

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