Chemistry - Concentration Terms Question with Solution | TestHub

$\text{1000}{\text{cm}}^{\text{3}}\text{of}\text{0}\text{.1}\text{M}\text{solution}\equiv \text{0}\text{.1}\text{mol}{\text{I}}_{\text{2}}$
So$1{\text{cm}}^{\text{3}}\text{of}\text{solution}\equiv 0.1\times {10}^{-3}\text{mol}{\text{I}}_{\text{2}}$
Hence$\text{1}\text{mol}{\text{I}}_{\text{2}}$contains$=6.02\times {10}^{23}{\text{I}}_{\text{2}}$molecules
So$0.1\times {10}^{-3}\text{mol}{\text{I}}_{\text{2}}$contains
$=6.02\times {10}^{23}\times 0.1\times {10}^{-3}{\text{I}}_{\text{2}}$molecules
$=12.04\times {10}^{19}{\text{I}}_{\text{2}}$atoms.