Chemistry - Concentration Terms Question with Solution | TestHub

No. of sodium lauryl sulphate$\left({\text{CH}}_3{\left({\text{CH}}_2\right)}_{11}{\text{SO}}_4^{-}{\text{Na}}^{+}\right)$in$1$litre solution

$={10}^{-3}\times 6\times {10}^{23}$

$=6\times {10}^{20}$

No. of sodium lauryl sulphate per${\text{mm}}^{\text{3}}=6\times {10}^{14}$

No. of colloidal particles per${\text{mm}}^{\text{3}}={10}^{13}$

No. of molecules per colloidal particle

$=\frac{6\times 10^{14}}{10^{13}}$

$=60$