Chemistry - Concentration Terms Question with Solution | TestHub

ChemistryConcentration TermsConcentration termMedium2 minPYQ_2020

ChemistryMediumassertion reason

The strengths of $5.6$ volume hydrogen peroxide (of density $1 g / mL$ ) in terms of mass percentage and molarity $(M)$ respectively, are: (Take molar mass of hydrogen peroxide as $34 g / mol$ )

Options:

Answer:

Solution:

For $H_{2} O_{2}$

Molarity $= \frac{Volume strength}{11.2} = \frac{5.6}{11.2} = 0.5 M$

Molarity $\frac{% (w / w) \times 10 \times d}{GMM}$

$0.5 = \frac{% (w / w) \times 10 \times 1}{34}$

$% (w / w) = \frac{0.5 \times 34}{10} = 1.7$

Stream:JEESubject:ChemistryTopic:Concentration TermsSubtopic:Concentration term

⏱ 2mℹ️ Source: PYQ_2020

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