150 mL of 0.4 M NaOH solution is mixed with 250 mL of 0.2 M NaOH solution. The final volume of the solution is 400 mL . What is the final molarity of NaOH in the mixed solution? (Report your answer by

Question

150 mL of 0.4 M NaOH solution is mixed with 250 mL of 0.2 M NaOH solution. The final volume of the solution is 400 mL . What is the final molarity of NaOH in the mixed solution? (Report your answer by multiplying the molarity by 1000 and rounding to the nearest integer).

TestHub · Accepted Answer

To find the final molarity, first calculate the moles of NaOH from each solution:

Moles (1) = $0.150 L \times 0.4 M = 0.060 m o l$

Moles (2) = $0.250 L \times 0.2 M = 0.050 m o l$

Total moles = $0.060 m o l + 0.050 m o l = 0.110 m o l$

Final molarity = $0.110 m o l /0.400 L = 0.275 M$

Multiplying by 100 gives $275$

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