Chemistry - Concentration Terms Question with Solution | TestHub

$2\mathrm{L}$ of $3\mathrm{M}{\mathrm{AgNO}}_3$ will contains 6 moles of ${\mathrm{AgNO}}_3$ $3\mathrm{L}$ of $1\mathrm{M}{\mathrm{BaCl}}_2$ will contain 3 moles of ${\mathrm{BaCl}}_2$ $2{\mathrm{AgNO}}_3+{\mathrm{BaCl}}_2⟶2\mathrm{AgCl}$ $+\mathrm{Ba}{\left({\mathrm{NO}}_3\right)}_2$ So, 6 moles of ${\mathrm{AgNO}}_3$ will react with 3 moles on ${\mathrm{BaCl}}_2$ it means, two solution will react completely to form 3 moles of $\mathrm{Ba}{\left({\mathrm{NO}}_3\right)}_2\equiv 6$ moles of ${\mathrm{NO}}_3^{-}$ions in $2+$ $3=5\mathrm{L}$ solution Hence, molarity of ${\mathrm{NO}}_3^{-}=\frac{6}{5}=1.2\mathrm{M}$