500 ml of 2 M CH 3 COOH solution is mixed with 600 ml 12% w / v CH 3 COOH solution then calculate the final molarity of solution.

Question

500 ml of 2 M CH 3 ​ COOH solution is mixed with 600 ml 12% w / v CH 3 ​ COOH solution then calculate the final molarity of solution.

TestHub · Accepted Answer

12 gm CH₃COOH is present in 100 ml of solution.

120 gm CH₃COOH is present in 1000 ml of solution.

$M_{2} = \frac{120}{60} = 2$

Now we are mixing:

$500 m l, 2 MC H_{3} COO H + 2 M, 600 m lC H_{3} COO H M_{1} V_{1} + M_{2} V_{2} = M_{3} V_{3} 500 \times 2 + 600 \times 2 = M_{3} \times 1100 M_{3} = \frac{2200}{1100} = 2$

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