Chemistry - Concentration Terms Question with Solution | TestHub

The decomposition of hydrogen peroxide is $2{\text{H}}_2{\text{O}}_2(aq)\to 2{\text{H}}_2\text{O}(l)+{\text{O}}_2(g)$. From the stoichiometry, $2$ moles of ${\text{H}}_2{\text{O}}_2$ produce $1$ mole of ${\text{O}}_2$. At STP, $1$ mole of ${\text{O}}_2$ occupies $22.4\text{L}$. Therefore, $2$ moles of ${\text{H}}_2{\text{O}}_2$ produce $22.4\text{L}$ of ${\text{O}}_2$. This means $1$ mole of ${\text{H}}_2{\text{O}}_2$ produces $11.2\text{L}$ of ${\text{O}}_2$. By definition, a $1\text{M}$ ${\text{H}}_2{\text{O}}_2$ solution produces $11.2\text{L}$ of ${\text{O}}_2$ at STP from $1\text{L}$ of solution, meaning it has a volume strength of $11.2$. Thus, a $11.2$ volume strength ${\text{H}}_2{\text{O}}_2$ solution has a molarity of $1.0\text{M}$. Therefore, option B is correct.