For the reaction 2 NO ( g ) + H 2 ( g ) → N 2 O ( g ) + H 2 O ( g ) , the following data are obtained. Experiment I: When p H 2 is constant (r = rate of reaction ) If p NO = 360 t orr , r

Question

For the reaction 2 NO ( g ) + H 2 ​ ( g ) → N 2 ​ O ( g ) + H 2 ​ O ( g ) , the following data are obtained. Experiment I: When p H 2 ​ ​ is constant (r = rate of reaction ) If p NO ​ = 360 t orr , r = 1.60 t orr s − 1 If p NO ​ = 180 t orr , r = 0.40 t orr s − 1 Experiment II: When p NO ​ is constant: If p H 2 ​ ​ = 360 t orr , r = 1.2 t orr s − 1 If p H 2 ​ ​ = 180 t orr , r = 0.6 t orr s − 1 The overall order of the reaction is:

TestHub · Accepted Answer

For p H 2 ​ ​ = constant, we have r 2 ​ r 1 ​ ​ = [ ( p NO ​ ) 2 ​ ( p NO ​ ) 1 ​ ​ ] m . This gives m = 2 when the values of data are substituted in the expression. For p NO ​ = constant, we have r 2 ​ r 1 ​ ​ = [ ( p H 2 ​ ​ ) 2 ​ ( p H 2 ​ ​ ) 1 ​ ​ ] n . This gives n = 1 when the values of data are substituted in the expression. The over all order is n + m = 3 .

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