For a process A + B ⟶ product, the reaction is second order with respect to A and zero order with respect to B . When 1.0 mole each of A and B are taken in a one litre vessel if the initial rate is 1

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For a process A + B ⟶ product, the reaction is second order with respect to A and zero order with respect to B . When 1.0 mole each of A and B are taken in a one litre vessel if the initial rate is 1 × 1 0 − 2 mole / L sec . The rate of the reaction when 50% of the reactants have been converted to products would be :-

TestHub · Accepted Answer

The rate law is R a t e = k [ A ] 2 . After 50% conversion, [ A ] halves, so the rate becomes ( 1/2 ) 2 = 1/4 of the initial rate. 1/4 × 1 × 1 0 − 2 = 2.5 × 1 0 − 3 mol / L sec .

Chemistry - Chemical Kinetics Question with Solution | TestHub

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