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ChemistryChemical KineticsFirst Order ReactionsEasy2 minPYQ_2024

ChemistryEasynumerical

Time required for $99.9%$ completion of a first order reaction is _______ times the time required for completion of $90%$ reaction.(nearest integer)

Answer:

3.00

Solution:

$K = \frac{1}{t _{99.9%}} ln (\frac{100}{0.1}) = \frac{1}{t _{90%}} ln (\frac{100}{10}) t_{99.9%} = t_{90%} \frac{ℓ n ( 1 0 ^{3} )}{ℓ n 10} t_{99.9%} = t_{90%} \times 3$

Stream:JEESubject:ChemistryTopic:Chemical KineticsSubtopic:First Order Reactions

⏱ 2mℹ️ Source: PYQ_2024

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