In the following reaction, 2 SO 2 ( g ) + O 2 ( g ) → 2 SO 3 ( g ) The r | TestHub

Passage / Comprehension

The reaction rate is the increase in molar concentration of product of a reaction per unit time or the decrease in molar concentration of reactant per unit time. However, due to the stoichiometry of the balanced chemical reaction, rates of reactions in terms of individual reactants and products are related.

$m_{1} A + m_{2} B \to n_{1} C + n_{2} D$ ,

Instantaneous rate of reaction = $- \frac{1}{m _{1}} \frac{d [ A ]}{d t} = - \frac{1}{m _{2}} \frac{d [ B ]}{d t} = + \frac{1}{n _{1}} \frac{d [ C ]}{d t} = + \frac{1}{n _{2}} \frac{d [ D ]}{d t}$

In appreciable interval of time, the average rate of reaction may be given as:

Average rate of reaction = $- \frac{1}{m _{1}} \frac{Δ [ A ]}{Δ t} = - \frac{1}{m _{2}} \frac{Δ [ B ]}{Δ t} = + \frac{1}{n _{1}} \frac{Δ [ C ]}{Δ t} = + \frac{1}{n _{2}} \frac{Δ [ D ]}{Δ t}$

In the following reaction,

$2 SO_{2} (g) + O_{2} (g) \to 2 SO_{3} (g)$

The rate of formation of SO₃ is $100 g mi n^{- 1}$ . Hence, the rate of disappearance of O₂ is:

Options:

Answer:

Solution:

In the reaction

$2 SO_{2} (g) + 1 mol O_{2} (g) \to 2 mol 2 SO_{3} (g)$

$32 g$ $160 g$

$∵ 160 g$ of $SO_{3}$ is formed by 32 g of $O_{2}$

$∴ 100 g$ of $SO_{3}$ will be formed by $\frac{32}{160} \times 100$ or 20 g of $O_{2}$

∴ Rate of disappearance of $O_{2} = 20 g min^{- 1}$

Chemistry - Chemical Kinetics Question with Solution | TestHub

Options:

Doubts & Discussion