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Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsArrhenius EquationEasy2 minPYQ_2011

ChemistryEasysingle choice

A chemical reaction was carried out at $300 K$ and $280 K$ . The rate constants were found to be $k_{1}$ and $k_{2}$ respectively. Then

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Answer:

Solution:

For every $1 0^{\circ}$ rise in temperture, Rate gets double. Hence, in this case rate constant will become four time. (d) $i . e$ ., $k_{1} = 4 k_{2} k_{2} = 0.25 k_{1}$ as the Rise in temperature given is $2 0^{\circ} C$

Stream:VITEEESubject:ChemistryTopic:Chemical KineticsSubtopic:Arrhenius Equation

⏱ 2mℹ️ Source: PYQ_2011

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