Chemistry - Chemical Kinetics Question with Solution | TestHub

According to the Arrhenius equation:

$k=A{e}^{-E_a/RT}$

This can be expressed in terms of base 10 as:

$k=A\times 10^{-E_a/2.303RT}$

Given $A=1.6\times 10^{13}{\text{ s}}^{-1}$ and $\frac{E_a}{2.303RT}=21$, substituting these values:

$k=1.6\times 10^{13}\times 10^{-21}$

$k=1.6\times 10^{-8}{\text{ s}}^{-1}$

Answer: $1.6\times 10^{-8}$