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Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsSecond & nth Order ReactionsHard2 minPYQ_2007

ChemistryHardsingle choice

$⟶_{82} Pb^{208}$ . The number of $α$ and $β$ -particles emitted during the above reaction is

Options:

Answer:

Solution:

No. of $α$ particles $= \frac{232 - 208}{4} = \frac{24}{4} = 6 α$ No. of $β$ particles $= 2 \times 6 - (90 - 82)$ $= 12 - 8 = 4 β$ Hence, $6 α$ and $4 β$ particles are emitted.

Stream:MHT_CETSubject:ChemistryTopic:Chemical KineticsSubtopic:Second & nth Order Reactions

⏱ 2mℹ️ Source: PYQ_2007

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