Chemistry - Chemical Kinetics Question with Solution | TestHub

$\begin{array}{rl}\text{ : Rate }& =\frac{\text{ concentration }}{\text{ time }}=\frac{\mathrm{mol}{\mathrm{L}}^{-1}}{\mathrm{s}}\\ =& \mathrm{mol}{\mathrm{L}}^{-1}{\mathrm{s}}^{-1}\end{array}$ $\begin{array}{rl}:\text{ Rate }& =\frac{\text{ concentration }}{\text{ time }}=\frac{\mathrm{mol}{\mathrm{L}}^{-1}}{\mathrm{s}}\\ & =\mathrm{mol}{\mathrm{L}}^{-1}{\mathrm{s}}^{-1}\end{array}$ The units of rate constant for the reaction of the $n^{\text{th }}$ order $={\left(\mathrm{mol}{\mathrm{L}}^{-1}\right)}^{1-n}{\mathrm{s}}^{-1}$ here, $=\frac{3}{2}$ $\therefore$ Unit of rate constant $={\left(\mathrm{mol}{\mathrm{L}}^{-1}\right)}^{1-3/2}{\mathrm{s}}^{-1}$ $={\left(\mathrm{mol}{\mathrm{L}}^{-1}\right)}^{-1/2}{\mathrm{s}}^{-1}$ $={\mathrm{mol}}^{-1/2}{\mathrm{L}}^{1/2}{\mathrm{s}}^{-1}$