For the adsorption of hydrogen on platinum, the activation energy is 30 kJ mol – 1 and for the adsorption of hydrogen on nickel, the activation energy is 41 . 4 kJ mol – 1 . The logarithm of the ratio

Question

For the adsorption of hydrogen on platinum, the activation energy is $30 kJ {mol}^{- 1}$ and for the adsorption of hydrogen on nickel, the activation energy is $41.4 kJ {mol}^{- 1} .$ The logarithm of the ratio of the rates of chemisorption on equal areas of the metals at $300 K$ is $_______$ (Nearest integer)

Given: $In 10 = 2.3$

$R = 8.3 J K^{- 1} {mol}^{- 1}$

TestHub · Accepted Answer

According to Arrhenius's equation, k = Ae - E a / RT logk = logA - E a 2 . 3 RT E a 1 = For the adsorption of hydrogen on platinum, the activation energy E a 2 = for the adsorption of hydrogen on nickel, the activation energy log k 2 k 1 = E a 2 - E a 1 2 . 3 RT = 11 . 4 × 1000 2 . 3 × 8 . 3 × 300 = 1 . 990 ≈ 2

Chemistry - Chemical Kinetics Question with Solution | TestHub

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