Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

For given first order reaction, the reactant reduces to 1/4th its initial value in 10 min. The rate constant of the reaction is

Options:

Answer:

Solution:

For the first order reaction,

$k = \frac{2.303}{t} \log \frac{a}{a - x}$

Given, $t = 10 min$

$a = a$

$a - x = \frac{a}{4}$

$k = \frac{2.303}{10} \log \frac{a}{\frac{a}{4}}$

$= \frac{2.303 \times 2}{10} \log 2$

$= 0.1386 mi n^{- 1}$

Stream:NTA_ABHYASSubject:ChemistryTopic:Chemical KineticsSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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