Chemistry - Chemical Kinetics Question with Solution | TestHub

The reaction is zero order.

$$-\frac{1}{4}\frac{\mathrm{d}[\mathrm{A}]}{\mathrm{dt}}={\mathrm{K}}_{reaction}$$

So,

$$-\frac{\mathrm{d}[\mathrm{A}]}{\mathrm{dt}}=4\times \mathrm{K}=20mm/sec$$

Now, at $t$,

$$A=A_0-K\times t$$

$$p_{\mathrm{A}}=4000-20\times 100$$

$$p_{\mathrm{A}}=2000\mathrm{mm}\mathrm{of}\mathrm{Hg}$$

Now, $p_{\mathrm{B}}=\frac{3}{4}\times 500=1500.00$

Now, $T_{final}=P_{\mathrm{A}}=0$, so $t=200\sec$.

So, after $250\sec$,

$$P_{\mathrm{T}}=\frac{3}{4}\times 4000+\frac{2}{4}\times 4000$$

$$P_{\mathrm{T}}=3000+2000=5000$$