Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsZero Order ReactionsMedium2 minPYQ_2021
ChemistryMediumnumerical

For the reaction, aA+bBcC+dD, the plot of log k v/s 1 T is given below:

The temperature at which the rate constant of the reaction is 10-4 s-1 is _____ K.
(Rounded-off to the nearest integer) [Given : The rat5e constant of the reaction is 10-5 s-1 at 500 K.]

Answer:
526.00
Solution:

log k=log A-Ea2.303RT

Slope= Ea 2.303R=10,000

logk2 k1=Ea2.303R1 T1-1 T2

log10-410-5=10,0001500-1 T2

log10-410-5=10,0001500-1 T2

T2=526.31526 K

Hence answer is 526

Stream:JEESubject:ChemistryTopic:Chemical KineticsSubtopic:Zero Order Reactions
2mℹ️ Source: PYQ_2021

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