Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsArrhenius EquationMedium2 minQB

ChemistryMediumsingle choice

Passage / Comprehension

From the following kinetic data answer the questions for the given reaction :

A + B → P

The energy of activation for reaction $(kcal / mol)$ is $(lo g 2 = 0.3)$ :-

Answer:

Solution:

$lo g (\frac{r _{2}}{r _{1}}) = \frac{E _{a}}{2.303 R} (\frac{1}{T _{1}} - \frac{1}{T _{2}})$

$lo g 4 = \frac{E _{a}}{2.303 \times 2} [\frac{1}{300} - \frac{1}{400}] E_{a} = 3.3 kcal / mol$

Stream:JEESubject:ChemistryTopic:Chemical KineticsSubtopic:Arrhenius Equation

⏱ 2mℹ️ Source: QB

Loading discussions...