Rate constant ( k ) of elementary reaction A ( g ) ⟶ B ( g ) at 2 7 ∘ C [in (seconds) − 1 ] is ____ × 1 0 7 . [Given : Units of ' k ' in (second) − 1 ]

lo g k = 10 − 300 600 = 8 k = 1 0 8 = 10 × 1 0 7

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Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsCollision TheoryMedium2 minQB

ChemistryMediumnumerical

Passage / Comprehension

Collision theory states that every reaction proceeds by the collision between the reactant molecules.

However, to bring about a chemical reaction, the reactants must collide with a certain minimum amount of energy and proper orientation. Such collisions which lead to the formation of products are called effective collisions. The rate constant of a reaction is written as $k = A e^{- E_{a} / RT}$ .

Rate constant $(k)$ of elementary reaction $A (g) ⟶ B (g)$ at $2 7^{\circ} C$ [in (seconds) $^{- 1}$ ] is $____$ $\times 1 0^{7}$ . [Given : Units of ' k ' in (second) $^{- 1}$ ]

Answer:

10.00

Solution:

$lo g k = 10 - \frac{600}{300} = 8$

$k = 1 0^{8} = 10 \times 1 0^{7}$

Stream:JEESubject:ChemistryTopic:Chemical KineticsSubtopic:Collision Theory

⏱ 2mℹ️ Source: QB

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