Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsRate of Reactions/Rate LawEasy2 minPYQ_2020

ChemistryEasysingle choice

The reaction $X \to$ product follows first order kinetics. In 40 minutes, the concentration of X changes from 0.1 M to 0.025 M, then the rate of reaction when concentration of X is 0.01 M is

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Answer:

Solution:

$k = \frac{2.303}{t} log \frac{C_{0}}{C_{t}} = \frac{2.303}{40} log \frac{0.1}{0.025}$
$= \frac{2.303}{40} l o g 4 = \frac{2.303 \times 0.6021}{40}$ $m i n^{- 1}$
$R a t e = k [A] = \frac{2.303 \times 0.6021}{40} m i n^{- 1} \times 0.01$ $M$
$= 3.47 \times 1 0^{- 4}$ $M / m i n$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Chemical KineticsSubtopic:Rate of Reactions/Rate Law

⏱ 2mℹ️ Source: PYQ_2020

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