Mechanism of a hypothetical reaction X 2 + Y 2 → 2XY is given below ( 1 ) X 2 → X + X (fast) ( 2 ) X + Y 2 ⇌ XY + Y (slow) ( 3 ) X + Y → XY (fast) The overall order of the reaction will be

X 2 → X + X (Fast) X + Y 2 ⇌ X Y + Y (Slow) As we know that slow step is Rate determine step ∴ R a t e = K X [ Y 2 ] (i) From last step K = X 2 X 2 X 2 = K 1 [ X 2 ] (ii) From equation (i)&(ii) Rate = K K 1 X 2 1 2 Y 2 Rate = K ' X 2 1 2 Y 2 Order = 1 2 + 1 = 1.5

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ChemistryChemical KineticsMiscellaneous/MixedEasy2 minPYQ_2020

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Mechanism of a hypothetical reaction
$X_{2} + Y_{2} \to 2XY$ is given below
$(1)$ $X_{2} \to X + X$ (fast)
$(2)$ $X + Y_{2} ⇌ XY + Y$ (slow)
$(3)$ $X + Y \to XY$ (fast)
The overall order of the reaction will be

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Answer:

Solution:

$X_{2} \to X + X$ (Fast)
$X + Y_{2} ⇌ X Y + Y$ (Slow)
As we know that slow step is
Rate determine step
$∴ R a t e = K [X] [Y_{2}]$ (i)
From last step
$K = \frac{{[X]}^{2}}{[X_{2}]}$
${[X]}^{2} = K_{1} [X_{2}]$ (ii)
From equation (i)&(ii)
Rate $= K \sqrt{K_{1}} {[X_{2}]}^{\frac{1}{2}} [Y_{2}]$
Rate $= K^{'} {[X_{2}]}^{\frac{1}{2}} [Y_{2}]$
Order $= \frac{1}{2} + 1 = 1.5$

Stream:NTA_ABHYASSubject:ChemistryTopic:Chemical KineticsSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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