Chemistry - Chemical Kinetics Question with Solution | TestHub

(A) $r=k[A]$ → first order, so $[A]$ decreases exponentially → graph (S)

(B) $r=k[A{]}^{1/2}[B{]}^{1/2}$, and $[A{]}_0=[B{]}_0$ ⇒ $r=k[A]$ → first order → graph (P)

(C) $r=k[A][B]$, with $[A{]}_0=[B{]}_0$ ⇒ $r=k[A{]}^2$ → second order → graph (R)

(D) $r=k[A{]}^0[B{]}^0=k$ → zero order → linear $t_{1/2}\propto [A{]}_0$ → graph (Q)

Hence, A→S, B→P, C→R, D→Q.