Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

A graph plotted between $\log t_{50}$ vs log concentration is a straight line. What conclusion can you draw from the given graph?

[Given: n = order of reaction]

Options:

Answer:

Solution:

$t_{\frac{1}{2}} \propto {(a)}^{1 - n}$
or $t_{\frac{1}{2}} = Z {(a)}^{^{1 - n}}$
or $\log t_{\frac{1}{2}} = \log Z + (1 - n) \log a$
or $(y) = c + m x$
Thus, slope = m = 1 - n
or 1 - n = 0
So n = 1
and for I order reaction $t_{\frac{1}{2}} = \frac{0.693}{k}$ .

Stream:NTA_ABHYASSubject:ChemistryTopic:Chemical KineticsSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...