The value of rate constant at 300 K is x × 1 0 7 M − 2 sec − 1 . Find x :

r = K [ A ] 3 3.2 × 1 0 − 2 = K ( 1 0 − 3 ) 3 k = 3.2 × 1 0 7

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ChemistryChemical KineticsRate of Reactions/Rate LawMedium2 minQB

ChemistryMediumnumerical

Passage / Comprehension

From the following data answer the question :

Reaction A + B → P

The value of rate constant at 300 K is $x \times 1 0^{7} M^{- 2} sec^{- 1}$ . Find x :

Answer:

3.20

Solution:

$r = K [A]^{3}$

$3.2 \times 1 0^{- 2} = K (1 0^{- 3})^{3}$

$k = 3.2 \times 1 0^{7}$

Stream:JEESubject:ChemistryTopic:Chemical KineticsSubtopic:Rate of Reactions/Rate Law

⏱ 2mℹ️ Source: QB

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