In the reaction of NO & H 2 which was present in their stoichiometric ratio at a pressure of 500 mmHg was half changed in 100 seconds. In another experiment, starting with stoichiometric ratio of NO

Question

In the reaction of NO & H 2 ​ which was present in their stoichiometric ratio at a pressure of 500 mmHg was half changed in 100 seconds. In another experiment, starting with stoichiometric ratio of NO & H 2 ​ at an initial pressure of 250 mm , the reaction was half completed in 200 seconds. Calculate the order of reaction.

TestHub · Accepted Answer

Since t 1/2 ​ ∝ a n − 1 1 ​ , we have t 2 ​ t 1 ​ ​ = ( a 1 ​ a 2 ​ ​ ) n − 1 = ( p 1 ​ p 2 ​ ​ ) n − 1 . Here, p 1 ​ = 500 mm , p 2 ​ = 250 mm , t 1 ​ = 100 sec , t 2 ​ = 200 sec . Thus, 200 100 ​ = ( 500 250 ​ ) n − 1 or n = 2 . i.e.order of reaction is 2 n d .

Chemistry - Chemical Kinetics Question with Solution | TestHub

Doubts & Discussion