Start Free Mock LoginAlready registered? Login here

Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

A graph plotted between $t_{\frac{1}{2}}$ vs. log concentration is a straight line. What conclusion can you draw from the given graph

Options:

Answer:

Solution:

$t_{\frac{1}{2}} α a^{1 - n}$

or $t_{\frac{1}{2}} = k a^{1 - n}$

$\log t_{\frac{1}{2}} = \log k + (1 - n) \log a$

so slope $= 1 - n$

or $1 - n = 0$

or $n = 1$

Stream:NTA_ABHYASSubject:ChemistryTopic:Chemical KineticsSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...