Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsMechanism of ReactionsMedium2 minQB

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For hypothetical reaction $A \to D$ takes place according to

Rate law will be: Assume the first step is a fast pre-equilibrium with constant K1=[C]/[A]. Find the rate of formation of product D (d[D]/dt). Express the answer in terms of [A] only, eliminating [C] using K1.

Options:

Answer:

Solution:

The rate-determining step is the slow step:

Rate $= k_{2} [A] [C]$ . Substitute $[C]$ from fast equilibrium: $[C] = K_{1} [A]$ .

Thus, Rate $= K_{1} k_{2} [A]^{2}$ .

Stream:JEESubject:ChemistryTopic:Chemical KineticsSubtopic:Mechanism of Reactions

⏱ 2mℹ️ Source: QB

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