Chemistry - Chemical Kinetics Question with Solution | TestHub

The rate constant$\left({\text{k}}^{\prime }\right)$of one reaction is double the rate constant$\left({\text{k}}^{″}\right)$of another reaction. Then the relationship between the corresponding activation energies of the two reactions$\left({\text{E}}_{\text{a}}{}^{\prime }\text{ and }{\text{E}}_{\text{a}}{}^{\prime \prime }\right)$will be -
(Assume the pre-exponential factor & temperature to be same)