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Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsRate of Reactions/Rate LawEasy2 minPYQ_2020

ChemistryEasysingle choice

The rate constant for the first-order reaction is $60 s^{- 1}$ . How much time will it take to reduce the concentration of the reactant to 1/16 of initial value?

Options:

Answer:

Solution:

$t = \frac{2.303}{k} log \frac{{[A]}_{0}}{[A]}$

$= \frac{2.303}{60} log \frac{a}{\frac{a}{16}} = \frac{2.303}{60} log 16$

$= \frac{2.303}{60} \times 1.204$

$= 0.0462 s$

$= 4.6 \times 10^{- 2} s$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Chemical KineticsSubtopic:Rate of Reactions/Rate Law

⏱ 2mℹ️ Source: PYQ_2020

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