Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsMiscellaneous/MixedEasy2 minPYQ_2020
ChemistryEasysingle choice

The rate of decomposition for methyl nitrite and ethyl nitrite can be given in terms of rate constant k1and k2respectively. The energy of activation for the two reactions are152.30 kJ mol-1 and 157.7 kJ mol-1as well as frequency factors are1013and1014respectively for the decomposition of methyl and ethyl nitrite. Calculate the temperature at which rate constant will be same for the two reactions.

Options:

Answer:
C
Solution:

k=Ae-EaRT

For methyl nitritek1=1013 e-152300/8.314×T

For ethyl nitritek2=1014 e-157700/8.314×T

Ifk1=k2then

1013 e-152300/8.314×T=1014 e-157700/8.314×T

Or2.303log10=157700 - 1523008.314 × T

T=282 K

Stream:NTA_ABHYASSubject:ChemistryTopic:Chemical KineticsSubtopic:Miscellaneous/Mixed
2mℹ️ Source: PYQ_2020

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