Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical Kineticskinetics of complexreaction Parallel, Reversible, SequentialMedium2 minQB

ChemistryMediuminteger

For the given sequential reaction

A $k_{1}$ B $k_{2}$ C

Initial concentration of A is 8 M. Calculate the approximate concentration of C after 10 min,

if $k_{1} = 2 \times 1 0^{8} mi n^{- 1}$ and $k_{2} = 0.0693 mi n^{- 1}$ .

Answer:

Solution:

A $k_{1}$ B $k_{2}$ C

t=0 8M 0 0

$k_{1} ≫ k_{2}$

$[C] = a (1 - e^{- k_{2} t})$ $a = 8 M$ , $k_{2} = 0.0693$ , $t = 10 min$

= $8 (1 - e^{- \frac{l n 2}{10} \times 10})$

$[C] = 4 M$

Stream:JEESubject:ChemistryTopic:Chemical KineticsSubtopic:kinetics of complexreaction Parallel, Reversible, Sequential

⏱ 2mℹ️ Source: QB

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