For the reaction, 2 S O 2 + O 2 ⇌ 2 S O 3 , the rate of disappearance of O 2 is 2 × 1 0 - 4 m o l L - 1 s - 1 . The rate of appearance of S O 3 is

2 S O 2 + O 2 ⇌ 2 S O 3 Rate of reaction = - 1 2 d [ S O 2 ] d t = - d [ O 2 ] d t = 1 2 d [ S O 3 ] d t 2 × 1 0 - 4 = 1 2 d [ S O 3 ] d t d [ S O 3 ] d t = 2 × 2 × 1 0 - 4 = 4 × 1 0 - 4 m o l L - 1 s - 1

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Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsRate of Reactions/Rate LawEasy2 minPYQ_2020

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For the reaction, $2 S O_{2} + O_{2} ⇌ 2 S O_{3}$ , the rate of disappearance of $O_{2}$ is $2 \times 1 0^{- 4}$ $m o l L^{- 1} s^{- 1}$ . The rate of appearance of $S O_{3}$ is

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Solution:

$2 S O_{2} + O_{2} ⇌ 2 S O_{3}$
Rate of reaction $= - \frac{1}{2} \frac{d [S O_{2}]}{d t} = - \frac{d [O_{2}]}{d t} = \frac{1}{2} \frac{d [S O_{3}]}{d t}$
$2 \times 1 0^{- 4} = \frac{1}{2} \frac{d [S O_{3}]}{d t}$
$\frac{d [S O_{3}]}{d t} = 2 \times 2 \times 1 0^{- 4} = 4 \times 1 0^{- 4} m o l L^{- 1} s^{- 1}$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Chemical KineticsSubtopic:Rate of Reactions/Rate Law

⏱ 2mℹ️ Source: PYQ_2020

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