Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsMiscellaneous/MixedEasy2 minPYQ_2020
ChemistryEasysingle choice

Consider the reaction A 2  B + C,  Δ H = - 1 5  kcal . The energy of activation of backward reaction is 20 kcal mol-1. In presence of catalyst, the energy of activation of forward reaction is 3 kcal mol-1. At 400 K the catalyst causes the rate of the forward reaction to increase by the number of times equal to-

Options:

Answer:
B
Solution:

E a f - E a b = Δ H = - 1 5  kcal

⇒    E a f = - 1 5 + 2 0 = 5  kcal

k catalyst k a = e E a - E a catalyst / RT

= e 5 - 3 × 1 0 3 / 2 × 4 0 0

= e 2 . 5

Stream:NTA_ABHYASSubject:ChemistryTopic:Chemical KineticsSubtopic:Miscellaneous/Mixed
2mℹ️ Source: PYQ_2020

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