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Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsRate of Reactions/Rate LawMedium2 minPYQ_2012

ChemistryMediumsingle choice

In the first order reaction, $75%$ of the reactant gets disappeared in 1.386 hours. The rate constant of the reaction is

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Answer:

Solution:

For a first order reaction, $k = \frac{2.303}{1.386 \times 60 \times 60} lo g \frac{a}{a - 0.75 a}$ $= \frac{2.303}{1.386 \times 60 \times 60} lo g 4$ $= 2.8 \times 1 0^{- 4} s^{- 1}$

Stream:JIPMERSubject:ChemistryTopic:Chemical KineticsSubtopic:Rate of Reactions/Rate Law

⏱ 2mℹ️ Source: PYQ_2012

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