Chemistry - Chemical Kinetics Question with Solution | TestHub

The average kinetic energy per molecule,

$=\frac{3}{2}\text{kT}$

Or$=\frac{3}{2}\frac{\text{R}}{{\text{N}}_{\mathrm{A}}}\text{T}$

$=\frac{3}{2}\times \frac{\text{8.314}}{\text{6.023}\times 10^{23}}\times 300$

$=\text{6.21}\times 10^{-21}{\text{J K}}^{-1}{\text{molecule}}^{-1}$