Chemistry - Chemical Kinetics Question with Solution | TestHub

$\mathrm{r}=\mathrm{k}\left[\mathrm{A}{]}^{\mathrm{x}}\right[\mathrm{B}{]}^{\mathrm{y}}$
$\text{5}\text{×}{\text{10}}^{-\text{3}}\text{=}\text{k(0}{\text{.1)}}^{\text{2}}{\text{(1)}}^{\text{y}}$...(1)
$2\text{×}{\text{10}}^{-\text{2}}\text{=}\text{k(0}{\text{.1)}}^{\text{2}}{\text{(2)}}^{\text{y}}$...(2)
equation$1÷2$
${\left(\frac{\text{0}\text{.1}}{\text{0}\text{.1}}\right)}^{\text{x}}{\left(\frac{\text{1}}{\text{2}}\right)}^{\text{y}}\text{=}\left(\frac{{\text{5×10}}^{\text{–3}}}{{\text{2×10}}^{\text{–2}}}\right)$
${\left(\frac{1}{2}\right)}^{\mathrm{y}}=\left(\frac{1}{4}\right)$
$\mathrm{y}=2$
$\text{2}\text{.5}\text{×}{\text{10}}^{-\text{3}}\text{=}\text{k(0}{\text{.05)}}^{\text{x}}{\text{(1)}}^{\text{y}}$...(3)
equation$1÷3$
${\left(\frac{\text{0}\text{.1}}{\text{0}\text{.05}}\right)}^{\text{x}}{\left(\frac{\text{1}}{\text{1}}\right)}^{\text{y}}\text{=}\left(\frac{{\text{5×10}}^{\text{–3}}}{\text{2}{\text{.5×10}}^{\text{–3}}}\right)$
${\left(\frac{100}{50}\right)}^{\mathrm{x}}=2$
$\mathrm{x}=1$
Order of reaction will respect to$\text{A}$and$\text{B}$respectively are$\text{1}$and$\text{2}$