Chemistry - Chemical Kinetics Question with Solution | TestHub

For $1^{\text{st }}$ order reaction. ${\mathrm{t}}_{1/2}\text{ (halflife time) }=\frac{0.693}{\mathrm{K}}$ Hence $\mathrm{K}=\frac{0.693}{{\mathrm{t}}^{1/2}}=\frac{0.693}{(60+40)\sec }=0.693\times$ $10^{-2}{\sec }^{-1}=6.93\times 10^{-3}{\sec }^{-1}$