Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsRate of Reactions/Rate LawEasy2 minPYQ_2020

ChemistryEasysingle choice

The rate law for reaction between the substances A and B is given by

$Rate = k {[A]}^{n} {[B]}^{m}$

On doubling the concentration of A and halving the concentration of B, the ratio of the new rate to the earlier rate of reaction will be

Options:

Answer:

Solution:

$\begin{array}{l} E a r l i e r R a t e = k {[A]}^{n} {[B]}^{m} \\ N e w r a t e = k {[2 a]}^{n} {[\frac{1}{2} b]}^{m} \\ \frac{N e w R a t e}{E a r l i e r R a t e} = {[2]}^{n} {[\frac{1}{2}]}^{m} = {[2]}^{n - m} \end{array}$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Chemical KineticsSubtopic:Rate of Reactions/Rate Law

⏱ 2mℹ️ Source: PYQ_2020

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