For the reaction, 2 N 2 O 5 g → 4 N O 2 g + O 2 ( g ) If the concentration of N O 2 increases by 5.2 × 10 - 3 M in 100 s then the rate of the reaction is:

Rate of reaction = 1 4 d N O 2 d t = 5.2 × 10 - 3 4 × 100 = 1.3 × 10 - 5 M s - 1

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Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsRate of Reactions/Rate LawEasy2 minPYQ_2020

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For the reaction,

$2 N_{2} O_{5} (g) \to 4 N O_{2} (g) + O_{2} (g)$

If the concentration of $N O_{2}$ increases by $5.2 \times 10^{- 3} M$ in 100 s then the rate of the reaction is:

Options:

Answer:

Solution:

Rate of reaction $= \frac{1}{4} \frac{d [N O_{2}]}{d t} = \frac{5.2 \times 10^{- 3}}{4 \times 100}$

$= 1.3 \times 10^{- 5} M s^{- 1}$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Chemical KineticsSubtopic:Rate of Reactions/Rate Law

⏱ 2mℹ️ Source: PYQ_2020

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