When sulphur in the form of S 8 is heated at 900 K , the initial pressure of one atm falls by 29% at equilibrium. This is because of conversion of some S 8 to S 2 . Find the value of equilibrium

Question

When sulphur in the form of S 8 ​ is heated at 900 K , the initial pressure of one atm falls by 29% at equilibrium. This is because of conversion of some S 8 ​ to S 2 ​ . Find the value of equilibrium constant for this reaction.

TestHub · Accepted Answer

S 8 ​ ⇌ 4 S 2 ​ 1 a t m , 0 1 − x 4 x Fall in pressure = x = 29% o f 1 a t m = 0.29 . x = 0.29 K ​ = P S 8 ​ ​ ( P S 2 ​ ​ ) 4 ​ = ( 1 − x ) ( 4 x ) 4 ​ K ​ = 0.71 ( 1.16 ) 4 ​ = 0.71 1.81 ​ = 2.55 a t m 3

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