Chemistry - Chemical Equilibrium Question with Solution | TestHub

ChemistryChemical EquilibriumProblems involving more than one equilibriumMedium2 minQB

ChemistryMediuminteger

Consider the reaction $N_{2} O_{4} (g) ⇌ 2 NO_{2} (g)$ .

The temperature at which $K_{C} = 20.4$ and $K_{P} = 600.1$ , is $____$ K .

(Round off to the Nearest Integer).

[Assume all gases are ideal and $R = 0.0831 L ba r m o l^{- 1} K^{- 1}$

Answer:

354

Solution:

$N_{2} O_{4} (g) ⇌ 2 NO_{2} (g); Δ n_{g} = 2 - 1 = 1$

Now, $K_{p} = K_{c} \cdot (RT)^{Δ n_{g}}$

or, $600.1 = 20.4 \times (0.0831 \times T)^{1}$

$∴ T = 353.99 K = 354 K$

Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Problems involving more than one equilibrium

⏱ 2mℹ️ Source: QB

Loading discussions...