A sample of HI ( g ) is placed in flask at a pressure of 0.2 atm . At equilibrium the partial pressure of HI ( g ) is 0.04 atm . What is K p for the given equilibrium? 2HI(g) ⇌ H 2 (g) + I 2 (g)

Question

A sample of HI ( g ) is placed in flask at a pressure of 0.2 atm . At equilibrium the partial pressure of HI ( g ) is 0.04 atm . What is K p ​ for the given equilibrium? 2HI(g) ⇌ H 2 (g) + I 2 (g)

TestHub · Accepted Answer

2 HI ( g ) ⇌ H 2 ​ ( g ) + I 2 ​ ( g ) t = 0 , 0.2 atm t = t eq ​ , 0.2 − 2 p P P Partial pressure of HI of equilibrium = 0.04 0.2 − 2 P = 0.04 P = 0.08 K P ​ = ( 0.04 ) 2 0.08 × 0.08 ​ K P ​ = 4

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