X 2 ( g ) + Y 2 ( g ) ⇌ 2 XY ( g ) reaction was studied at a certain temperature. In the beginning 1 mole of X 2 was taken in a one litre flask and 2 moles of Y 2 was taken in another 2 litre

Question

X 2 ​ ( g ) + Y 2 ​ ( g ) ⇌ 2 XY ( g ) reaction was studied at a certain temperature. In the beginning 1 mole of X 2 ​ was taken in a one litre flask and 2 moles of Y 2 ​ was taken in another 2 litre flask and both these containers are connected so equilibrium can be established. What is the equilibrium concentration of X 2 ​ and Y 2 ​ ? Given Equilibrium concentration of [ XY ] = 0.4 moles / litre .

TestHub · Accepted Answer

Question Explanation:

Find the equilibrium concentrations of X and Y from the given concentration of XY.

Concept: This question is based on the calculation of $K_{c}$ .

Solution:

$X_{(g)} + Y_{(g)} ⇌ 2 X Y_{(g)}$

At $t = 0$ : $\frac{1}{3} M \frac{2}{3} M -$

At $t = t_{e q}$ : $\frac{1}{3} M - a \frac{2}{3} M - a 2 a$

Given $2 a = 0.4$ , therefore $a = 0.2$ .

$[X_{2}]_{e q} = \frac{1}{3} M - 0.2$

$[Y_{2}]_{e q} = \frac{2}{3} M - 0.2$

Final Answer: The correct option is (2).

Chemistry - Chemical Equilibrium Question with Solution | TestHub

Options:

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