The diamonds are formed from graphite under very high pressure. Given that the densities of graphite and diamond are, respectively, 2.0 and 3.0 g/cm³ and are independent of pressure. Δ f G° values for

Question

The diamonds are formed from graphite under very high pressure. Given that the densities of graphite and diamond are, respectively, 2.0 and 3.0 g/cm³ and are independent of pressure. Δ f G° values for graphite and diamond are zero and 3.2 kJ/mol, respectively. If the equilibrium pressure at which graphite is converted into diamond at 25°C is P bar, then the value of 0.01P is

TestHub · Accepted Answer

Molar volume of graphite = 12/2.0 = 6.0 cm³ Molar volume of diamond = 12/3.0 = 4.0 cm³

ΔV = 4.0 - 6.0 = -2.0 cm³/mol = -2.0 × 10^-6 m³/mol

At equilibrium ΔG = ΔG° + ΔV(P - 1 bar) = 0

3200 = (2.0 × 10^-6)(P-1)(10⁵)

P - 1 = 3200/0.2 = 16000, so P ≈ 16001 bar

0.01P ≈ 160

Answer is 0160

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