Chemistry - Chemical Equilibrium Question with Solution | TestHub
ChemistryChemical EquilibriumProblems involving more than one equilibriumHard2 minQB
ChemistryHardsingle choice
What is the formation equilibrium constant for ammonia?
Options:
Answer:
C
Solution:
Let nitrogen and hydrazine partial pressures be xp* and yp*; the total gives x+y = 5. Atom balances give the initial nitrogen-to-hydrogen molecular ratio (x+1+y)/(4+3+2y) = 6/11.
Thus 6/(7+2y) = 6/11, giving y = 2 and x = 3.
Kp = (2p*)2/[(3p*)(4p*)3] = 1/(48p*2).
This is option (c).
Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Problems involving more than one equilibrium
⏱ 2mℹ️ Source: QB
Doubts & Discussion
Loading discussions...
