Chemistry - Chemical Equilibrium Question with Solution | TestHub
Match Column I with Column II
Column I | Column II |
|---|---|
P) 2SO2(g) + O2(g) ⇌ 2SO3(g) | i) Unaffected by inert gas addition |
Q) NH4Cl(s) ⇌ NH3(g) + HCl(g) | ii) Forward shift by rise in pressure and backward shift by inert gas addition |
R) H2(g) + CO2(g) ⇌ H2O(g) + CO(g) | iii) Unaffected by increase in pressure |
S) C(s) + H2O(g) ⇌ CO(g) + H2(g) | iv) Backward shift by rise in pressure and forward shift by inert gas addition |
Options:
Answer:
Solution:
For reaction P, Δng = -1. A pressure rise shifts the equilibrium forward, and adding an inert gas at constant pressure shifts it backward. Thus, P-ii.
For reaction Q, gases appear only on the product side. A pressure rise shifts the equilibrium backward, and adding an inert gas at constant pressure shifts it forward. Thus, Q-iv.
For reaction R, Δng = 0. Therefore, pressure has no effect (iii), and adding an inert gas has no effect (i).
For reaction S, the number of gaseous moles changes from 1 to 2. A pressure rise shifts the equilibrium backward, and adding an inert gas at constant pressure shifts it forward. Thus, S-iv.
The correct mapping is option (d).
